Question

Question #f6853

Answer 1

Molar mass of `MgSO_4=24+32+4*16=120" g/mol"`

`7.5xx10^2mLor 0.75L" "0.000450M" " MgSO_4` solution contains `0.75xx4.5xx10^-4 mol " " MgSO_4`

`= 3.375xx10^-4 molxx120g/"mol"=4.05xx10^-2g " "MgSO_4`

`=40.5mg " "MgSO_4`

So `4.05mg " "MgSO_4` is to be taken taken in a 750mL volumetric flask and after dissolving it in water volume is made up to 750mL by adding water.