How do you solve #\frac { 1} { 4} ( 4x - 1) = 2x + \frac { 1} { 8}#?

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Answer 1 · 2016-10-29T17:33:02

Questions that begin with "How do you" are best answered by explanation. Please see below.

Given:

#1/4(4x - 1) = 2x + 1/8#

Distribute the #1/4#:

#x - 1/4 = 2x + 1/8#

Flip:

#2x + 1/8= x - 1/4#

Subtract x from both sides:

#x + 1/8= -1/4#

Subtract #1/8# from both sides

#x = -1/4- 1/8#

#x = -3/8#