How do you solve $- 2 (x + 9) - (9 - x) + 2 = 2 x - 1 + 5 x$ $-2(x+9) -(9-x) +2= 2x-1+5x$ ?

Question

581 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-29T18:11:21

$x = - 3$ $x = -3$

First expand everything in parenthesis:

$- 2 x - 18 - 9 + x + 2 = 2 x - 1 + 5 x$ $-2x - 18 - 9 + x + 2 = 2x - 1 + 5x$

The group like terms on each side of the equation:

$- x - 25 = 7 x - 1$ $-x - 25 = 7x - 1$

Then solve for $x$ $x$ while keeping the equation balanced:

$- x + x - 25 + 1 = 7 x + x - 1 + 1$ $-x + x -25 + 1 = 7x + x - 1 + 1$

$- 24 = 8 x$ $-24 = 8x$

$x = - 3$ $x = -3$

How do you solve −2(x+9)−(9−x)+2=2x−1+5x-2(x+9) -(9-x) +2= 2x-1+5x?