How do you solve #-2(x+9) -(9-x) +2= 2x-1+5x#?

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Answer 1 · 2016-10-29T18:11:21

#x = -3#

First expand everything in parenthesis:

#-2x - 18 - 9 + x + 2 = 2x - 1 + 5x#

The group like terms on each side of the equation:

#-x - 25 = 7x - 1#

Then solve for #x# while keeping the equation balanced:

#-x + x -25 + 1 = 7x + x - 1 + 1#

#-24 = 8x#

#x = -3#