How do you solve #8n ^ { 2} - 4= - 76#?

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Answer 1 · 2016-10-31T10:48:13

no solution in #RR#
#n = +-3i# in #CC#

#8n^2 - 4 = -76#

#=> 8n^2 = -72#

#=> n^2 = -9#

#=> n = +-3sqrt(-1)#

No solution in #RR#.

In #CC#, #sqrt(-1) = i#, so

#n = +-3i#