How do you solve #6y - ( 4- 2y ) = 3( 7+ 2y ) - 1#?

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Answer 1 · 2016-10-31T22:12:48

#y=color(blue)(12)#

Solve: #6y-(4-2y)=3(7+2y)-1#

Expand both sides using the distributive property: #a(b+c)=ab+ac#

#6y-4+2y=21+6y-1#

#Simplify.

#8y-4=20+6y#

Subtract #6y# from both sides.

#8y-6y-4=20#

Simplify.

#2y-4=20#

Add #4# to both sides.

#2y=20+4#

Simplify.

#2y=24#

Divide both sides by #2#.

#y=12/2#

Simplify.

#y=12#