How do you differentiate #g(y) =x(x^2 + 6) # using the product rule?
1 Answer
Nov 1, 2016
#dy/dx=3x^2+6#
Explanation:
Given -
#y=x(x^2+6)#
#dy/dx=[x(2x)+(x^2+6)(1)]#
#dy/dx=2x^2+x^2+6#
#dy/dx=3x^2+6#