How do you solve #(2x - 3) ( x - 2) = - 12x + 18#?

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Answer 1 · 2016-11-01T15:02:20

#(2x-3)(x-2)=-12x+18#

Expand using the foil method.

#2x^2-4x-3x+6=-12x+18#

#2x^2-7x+6=-12x+18#

Add #12x# and subtract #18# on both sides...

#2x^2-7x+6+12x-18=0#

#2x^2+5x-12=0#

Factorise...

#(2x-3)(x+4)=0#

When #x=3/2# and #x=-4#, what you get is #0#.

Therefore, the answers are:

#x=3/2#

#x=-4#