How do you solve #6( - 2m - 3) = 12#?

1 Answer
smendyka
Nov 2, 2016

#m = -2.5#

Explanation:

Step 1) Expand the terms in parenthesis
Step 2) Solve for #m# while keeping the equation balanced

#-12m - 18 = 12#

#-12m - 18 + 12m - 12 = 12 + 12m - 12#

#-30 = 12m#

#-30/12 = (12m)/12#

#m = -2.5#

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