How do you solve the system of equations #5x + y = 24# and #- 3x + 2y = - 4#?

1 Answer
Nov 2, 2016

#x=4# and #y=4#

Explanation:

#5x+y=24#
#-3x+2y=-4#

Multiply all terms in the first equation by #2#.

#10x+2y=48#
#-3x+2y=-4#

Subtract the second equation from the first equation.

#10x+2y=48#
#-(-3x+2y)=-(-4)#

Opening the brackets in the second equation we get:

#10x+2y=48#
#+3x-2y=+4#

Simplifying we get:

#13x=52#

Divide both sides by #13#.

#x=4#

Substitute #4# for #x# in either of the given equations.

  1. #5x+y=24#
    #(5xx4)+y=24#
    #20+y=24#
    Subtract 20 from each side.
    #y=4#

  2. #-3x+2y=-4#
    #(-3xx4)+2y=-4#
    #-12+2y=-4#
    Add #12# to both sides.
    #2y=8#
    Divide both sides by #2#.
    #y=4#

#:.y=4#