Question

Question #c2366

Answer 1

`(dy)/(dx)=2atan(ax+b)sec^2(ax+b)`

Explanation:

`y=tan^2(ax+b)`

`u=ax+b=>(du)/(dx)=a`

`y=tan^2u=>(dy)/(du)=2tanusec^2u`

`(dy)/(dx)=(dy)/(du)xx(du)/(dx)`

`(dy)/(dx)=(2tanusec^2u)xxa`

`(dy)/(dx)=2atan(ax+b)sec^2(ax+b)`