What is the #y#-intercept of #g(x)=-x^2+6x-8#?

1 Answer
Daavid M.
Nov 2, 2016

#y = -8#

Explanation:

Set #x = 0# in the function #g(x)#. By definition, the y-intercept is the value at which #x = 0#. Plugging this in, we're left with #g(0) = -8#. In general, the coordinate for the y-intercept is:

#(0, y#).

Similarly, the coordinate for the x intercept is

#(x, 0)#.

To find the x-intercept, you must set #g(x) = 0# and solve for x.

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