A soccer ball is kicked horizontally at 18.8 m/s off the top of a building and lands 33.9 meters from the building. What is the height of the building.? (round answer to 3 sig. figs) Answer: ______ m

1 Answer
Nov 3, 2016

#15.9m#, rounded to 3 sig. figs

Explanation:

The soccer ball travels a horizontal distance of #33.9m# after being kicked with horizontal velocity of #18.8ms^-1#. Assuming air resistance is negligible.

Time of flight of the ball #t="Distance"/"Speed"=33.9/18.8s#

In the vertical direction kinematic equation is
height #h=ut+1/2g t^2#
Initial velocity #u_v=0#, acceleration due to gravity #g=9.81ms^-2#. Inserting various values we get
#h=0xx33.9/18.8+1/2xx9.81xx (33.9/18.8)^2#
#=>h=1/2xx9.81xx (33.9/18.8)^2#
#=>h=15.9m#, rounded to 3 sig. figs