Question

How do you solve `y^ { 2} - 36= 5y`?

Answer 1

`{-4,9}`

Explanation:

`y^2-36=5y`
set it equal to zero
`y^2-5y-36=0`
factor
`(y-9)(y+4)=0`

`(y-9)=0`
`y=9`

`(y+4)=0`
`y=-4`

`{-4,9}`