How do you evaluate #9!#? Precalculus The Binomial Theorem The Binomial Theorem 1 Answer sjc Nov 3, 2016 #362880# Explanation: in general #(n!)=n(n-1)(n-2)(n-3)....1# so #(9!)=9xx8xx7xx6xx5xx4xx3xx2xx1# #=362880# Answer link Related questions What is the binomial theorem? How do I use the binomial theorem to expand #(d-4b)^3#? How do I use the the binomial theorem to expand #(t + w)^4#? How do I use the the binomial theorem to expand #(v - u)^6#? How do I use the binomial theorem to find the constant term? How do you find the coefficient of x^5 in the expansion of (2x+3)(x+1)^8? How do you find the coefficient of x^6 in the expansion of #(2x+3)^10#? How do you use the binomial series to expand #f(x)=1/(sqrt(1+x^2))#? How do you use the binomial series to expand #1 / (1+x)^4#? How do you use the binomial series to expand #f(x)=(1+x)^(1/3 )#? See all questions in The Binomial Theorem Impact of this question 3921 views around the world You can reuse this answer Creative Commons License