Question

How do you evaluate the definite integral `int sinxdx` from `[pi/3, pi]`?

Answer 1

`3/2`

Explanation:

`int_(pi/3)^(pi)sinxdx`

`[-cosx}_(pi/3)^pi`

`[-cos(pi)]-[-cos(pi/3)]`

`-(-1)-(-1/2)`

`=1+1/2=3/2`