How do you solve #5( y - 2) - 7y = - 32#?

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Answer 1 · 2016-11-03T22:09:03

#y = 11#

Step 1) Expand the terms in the parenthesis
Step 2) Combine like terms
Step 3) Solve for #y# while keeping the equation balanced

#5y - 10 - 7y = -32#

#(5 - 7)y - 10 = - 32#

#-2y - 10 = -32#

#-2y - 10 + 2y + 32 = -32 + 2y + 32#

#22 = 2y#

#22/2 = (2/2)y#

#11 = 1y#

#y = 11#