Three consecutive integers have a sum of 78. How do you find the integers?

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Answer 1 · 2016-11-05T08:33:34

#25#, #26# and #27# are the three consecutive integers.

Let the numbers be represented as #x#, #x+1# and #x+2#.

We can write the equation:

#x+(x+1)+ (x+2)=78#

Opening the brackets and simplifying:

#x+x+1+x+2=78#

#3x+3=78#

Subtract #3# from both sides.

#3x=75#

Divide both sides by #3#.

#x=25#

Since the three consecutive integers are #x#, #x+1# and #x+2#, replace #x# with #25#.

#:. 25#, #26# and #27# are the three consecutive integers.