In the set of real numbers, what is the domain of #f(x)=sqrt(x+5)#?

1 Answer
Nov 6, 2016

The domain, or allowed values of #x#, is #x>=-5#. In interval notation, the domain is #[-5,oo)#.

Explanation:

For real numbers, the expression under the square root must be greater than or equal to zero. In other words, you can't take a square root of a negative.

#f(x)=sqrt(x+5)#

#x+5 >= color(white)a0#
#color(white)(a)-5color(white)(a^2)-5color(white)(aaa)#Subtract #5# from both sides

#color(white)(aa)x>= -5#

In interval notation, #x>= -5# is written #[-5, oo)#