Question #8252f

1 Answer
Nov 6, 2016

depends on which logs you use.

Explanation:

log(2^(x^3)) is the same as x^3log(2)

so we end up with:" "x^3log(2)=6

=>x^3=6/log(2)

x= root(3)(6/log(2))

The value of x will vary depending on what type of logs you use.

The usual is either log_10" or "log_e where log_e is normally written as ln

x= root(3)(6/log_10(2)) ~~2.7113 to 4 decimal places

x= root(3)(6/ln(2))~~2.0533 to 4 decimal places