Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-45 C` and `60 C` that are `15 m` apart?

Answer 1

Force 'F' in terms of coulomb's constant 'k' is -12k Newtons.

Explanation:

According to the Coulomb's Law
`F = (kq_1q_2)/r^2`.
Here the coulomb's constant 'k' is often written as `1/(4piepsilon_"0")` so that the force equation becomes
`F = [1/(4piepsilon_"0")][(q_1q_2)/r^2]`
In S.I units , the coulomb's constant 'k' is measured to be `8.98755xx10^9 N m^2 C^-2 ~~9xx10^9 Nm^2C^-2`
By substituting the given values in terms of 'k' we get,
Force`F = [k(-45)(60)]/(15)^2=-12k` Newtons.
In terms of numericals `F = -108xx10^9`Newtons.