How do you solve #6^{(x+7)}+6^{(x+2)}=2#?

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Answer 1 · 2016-11-07T21:05:21

#6^{(x+7)}+6^{(x+2)}=2#

#6^x*6^7+6^x*6^2 = 2#

#6^x(6^7+6^2) = 2#

#6^x = 2/(6^7+6^2)#

#x = log_6 (2/(6^7+6^2))#

#x = -log_6 ((6^7+6^2)/2)#

#x = -log_6 (139,986)#

# = -ln(139,986)/ln(6)#