Question

How do you find the derivative of `g(t)=t^2 2^t`?

Answer 1

`g'(t)=2^(t+1)t+ 2^(t)t^2ln2`

Explanation:

Let's rewrite it `g(t)=t^2e^(tln2)`
Now we can derive it

`g'(t)=2t*e^(tln2)+t^2ln2e^(tln2)` that can be rewritten as
`g'(t)=e^(tln2)*(2t+t^2ln2))=2^(t+1)*t+ 2^t*t^2ln2`