How do you find the derivative of g(t)=t^2 2^t? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Salvatore I. Nov 8, 2016 g'(t)=2^(t+1)t+ 2^(t)t^2ln2 Explanation: Let's rewrite it g(t)=t^2e^(tln2) Now we can derive it g'(t)=2t*e^(tln2)+t^2ln2e^(tln2) that can be rewritten as g'(t)=e^(tln2)*(2t+t^2ln2))=2^(t+1)*t+ 2^t*t^2ln2 Answer link Related questions How do I find f'(x) for f(x)=5^x ? How do I find f'(x) for f(x)=3^-x ? How do I find f'(x) for f(x)=x^2*10^(2x) ? How do I find f'(x) for f(x)=4^sqrt(x) ? What is the derivative of f(x)=b^x ? What is the derivative of 10^x? How do you find the derivative of x^(2x)? How do you find the derivative of f(x)=pi^cosx? How do you find the derivative of y=(sinx)^(x^3)? How do you find the derivative of y=ln(1+e^(2x))? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 3769 views around the world You can reuse this answer Creative Commons License