Question

How do you simplify `(4x ^ { 5} y ^ { - 4} ) ^ { - 2}`?

Answer 1

`=y^8/(16x^10)`

Explanation:

Deal with each term in the bracket separately

`(4x^5y^-4)^-2`

`4^-2x^(5xx-2)y^(-4xx-2)`

`1/4^2xxx^(-10)y^(+8)`

`=y^8/(16x^10)`