Question

How do you write the complex conjugate of the complex number `1 + 3i`?

Answer 1

The conjugate is `=1-3i`

Explanation:

Let `z=a+ib` be a complex number

The conjugate is `barz=a-ib`

Therefore, `z*barz=(a+ib)(a-ib)`

`=a^2-i^2b^2`
But `i^2=-1`

therefore `z*barz=a^2+b^2`