Question

How do you find the standard form of the following equation `Y=(x+3)^2+1`?

Answer 1

Standard form is `y=x^2+6x+10`

Explanation:

`y=(x+3)^2+1`

Multiply, or FOIL, the term being squared in the parentheses:
`y=(x+3)(x+3)+1`
`y=x^2+3x+3x+9+1`

Combine like terms:
`y=x^2+6x+10`