How do you add #\frac { 3p - 3} { p } + \frac { 6p - 6} { 5p ^ { 2} }#?

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Answer 1 · 2016-11-11T20:42:58

#(15p^2-9p-6)/(5p^2)" "# writing it another way #" "3-9/(5p)-6/(5p^2)#

Multiply by 1 and you do not change the value. However, 1 comes in many forms.

#color(green)([(3p-3)/p color(magenta)(xx1)]+(6p-6)/(5p^2))#

#color(green)([(3p-3)/p color(magenta)(xx(5p)/(5p))]+(6p-6)/(5p^2))#

#color(green)([(5p(3p-3))/(5p^2) ]+(6p-6)/(5p^2))#

Now that the denominators (bottom numbers) are the same you can directly add the top numbers (numerators).

#([15p^2-15p]+(6p-6))/(5p^2)#

#(15p^2-9p-6)/(5p^2)#

#3-9/(5p)-6/(5p^2)#