How do you separate and simplify #\frac { 32a ^ { 8} b ^ { 6} - 12a ^ { 5} b ^ { 4} c ^ { 2} } { 4a ^ { 3} b ^ { 3#?

Question

1167 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-12T02:12:52

The simplified value is

#8a^5b^3 - 3a^2bc^2#

I would begin by factoring out the denominator from each of the terms in the numerator.

#(32a^8b^6 - 12a^5b^4c^2)/(4a^3b^3)#

#(4a^3b^3(8a^5b^3 - 3a^2bc^2))/(4a^3b^3)#

Then cancel

#(cancel(4a^3b^3)(8a^5b^3 - 3a^2bc^2))/cancel(4a^3b^3)#

The simplified value is

#8a^5b^3 - 3a^2bc^2#