Question

How do you write the standard from of the equation of the circle given Center at (3, -6); radius = 5?

Answer 1

`(x - 3)^2 + (y + 6)^2 = 25`

Explanation:

Standard Equation of a circle

`(x - h)^2 + (y - k)^2 = r^2`

where:

`Center: (h, k)`
`radius: r`

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`(x - 3)^2 + (y + 6)^2 = 5^2`

`=> (x - 3)^2 + (y + 6)^2 = 25`