Question

How do you write the first six terms of the sequence `a_n=2^(n+3)`?

Answer 1

16, 32, 64, 128, 256, 512

Explanation:

You can substitute the natural numbers from 1 to 6 in the expression `2^(n+3)` to get:

`a_color(red)1=2^(color(red)1+3)=2^4=16`

`a_color(red)2=2^(color(red)2+3)=2^5=32`

`a_color(red)3=2^(color(red)3+3)=2^6=64`

`a_color(red)4=2^(color(red)4+3)=2^7=128`

`a_color(red)5=2^(color(red)5+3)=2^8=256`

`a_color(red)6=2^(color(red)6+3)=2^4=512`