Question #55de4

1 Answer
Nov 14, 2016

Assuming you meant log_a(a/sqrtx)-log_a(sqrtax)

1/2-3/2log_ax

Explanation:

log_a(a/sqrtx)-log_a(sqrtax)=log_a((a/sqrtx)/(sqrtax))=log_a(sqrta/(x sqrtx))=log_asqrta-log_ax^(3/2)=1/2-3/2log_ax