Question

How do you find the limit of `(1-cosh)^2/h` as `h->0`?

Answer 1

`0`

Explanation:

`lim_(h->0)(cos(0)-cos(h))/(0-h)=(d/(dh)cos(h))_(h=0)=-sin(0)=0` then

`lim_(h->0)(1-cos(h))^2/h=(lim_(h->0)(1-cos(h))/h)(lim_(h->0)(1-cos(h)))=0 cdot 0=0`