How do you write the equation #5^-3=1/125# in logarithmic form?

1 Answer
Jim G.
Nov 14, 2016

#log_5( 1/125)=-3#

Explanation:

Using the #color(blue)"laws of logarithms"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=nhArrx=b^n)color(white)(2/2)|)))#

Consider #1/125=5^(-3)#

#rArrx=1/125,b=5" and " n=-3#

#rArr5^(-3)=1/125tolog_5(1/125)=-3#

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