If #2/x >= 1/7# what is the largest possible value for #x#?

2 Answers
Nov 15, 2016

#color(green)(14)#

Explanation:

#2/14=1/7# ...so if #x=14# then #2/x = 1/7#

Note that #x# must be greater than zero for #2/x >=1/7# (otherwise #2/x# would be negative).
also if #x> 14# then #2/x < 1/7#

Nov 15, 2016

#x <= 14# , so the maximum value for #x# is 14.

Explanation:

As mentioned by Alan P., #x# has to be more than 0 ( ie positive)

It may not be equal to 0,
because it is in the denominator.
If it was negative, #2/x# could not be more than #1/7#

Now that we know that #x# is positive, there are 2 ways to solve this inequality..

  • multiply both sides by #7x# to cancel the denominators

#2/cancelx xx 7cancelx >= 1/cancel7 xx cancel7x#

#14 >= x" "rarr x <= 14#

  • invert both sides. (the inequality sign will change around)

#2/x >= 1/7#

#x/2 <= 7/1" "larr# multiply by 2

#x <= 14#