How many mols are in 23.7 g of #KMnO_4#?

1 Answer
anor277
Nov 15, 2016

#"Number of moles"# #=# #"Mass"/"Molar mass"#

Explanation:

And moles of #"potassium permanganate"# #=# #(23.7*g)/(158.03*g*mol^-1)# #~=1/6*mol#.

How many moles of oxygen atoms does this represent?

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