Question

The length of a rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m, how do you find the dimensions of the rectangle?

Answer 1

side 1 = 15m, s side 2 = 15m, side 3 = 25m, side 4 = 25m.

Explanation:

The perimeter of an object is the sum of all it's lengths. So in this problem, 80m = side1 + side2 + side3 + side4.

Now a rectangle has 2 sets of equal length sides.

So 80m = 2xSide1 + 2xSide2

And we are told that the length is 10m more than it's breadth.

So 80m = 2xSide1+(10+10) + 2xSide2

So 80m = 2xS1+20 +2S2

80 = 2x + 2y + 20

If it were a square, x + y would be the same

so

60 = 4x side1

so side 1 = 60/4 = 15m

So side 1 = 15m, side 2 = 15m, side 3 = 15m+10m side 4 = 15+10m

So s1 = 15m, s2 = 15m, s3 = 25m, s4 = 25m.

Perimiter = 80m and the length of th e rectangle is 10m longer than the breadth