What is the field strength, #E#, experienced by a test charge, #q#, if a charge of #1.0*10^-6# coulombs is placed on #q# and a force of #6.2# #N# is applied?

1 Answer
SaiGanesh Gotetti
Nov 16, 2016

The electric field #vec E # is #6.2 mu #coulombs

Explanation:

The electric field '#vecE#' at a point 'P' at a distance 'r' from 'Q'. Let us imagine a test charge 'q' placed at 'P'. The charge 'Q' creates a field '#vecE#' at 'P' and this field exerts a force
#vec F=qvecE#.
Calculating with given numericals we get
#vecE= ( 6.2N)//(1.0xx10^-6C)#
#:.vecE=6.2mu#Coulombs.

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