How do you solve #4^ { 2x - 2} = \frac { 1} { 4}#?

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Answer 1 · 2016-11-17T08:24:54

#x=1/2#

change the numbers to the same base.

note #1/4-4^-1#

#4^(2x-2)=1/4#

#4^(2x-2)=4^-1#

#=>2x-2=-1#

#2x=-1+2=1#

#=>x=1/2#