How do you solve #5^(-9.2x-9)-4=57#?

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Answer 1 · 2016-11-18T04:49:28

Isolate the term involving the variable, then take the #log_5# of both sides.

#5^(-9.2x-9)-4=57#

#5^(-9.2x-9)=61#

#log_5(5^(-9.2x-9))=log_5 61#

#-9.2x-9=log_5 61#

#-9.2x=log_5 61+9#

#x=-(log_5 61+9)/9.2#

#(xapprox-1.2559)#