How do you solve #4( x - 1) \leq - 5( x - 1)#?

1 Answer
Jim G.
Nov 18, 2016

#x<=1#

Explanation:

distribute the brackets on both sides of the inequality.

#rArr4x-4<=-5x+5#

add 5x to both sides.

#4x+5x-4<=cancel(-5x)cancel(+5x)+5#

#rArr9x-4<=5#

add 4 to both sides.

#9xcancel(-4)cancel(+4)<=5+4#

#rArr9x<=9#

To solve for x, divide both sides by 9

#(cancel(9) x)/cancel(9)<=9/9#

#rArrx<=1" is the solution"#

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