How do you solve #5+ 3x < 5#?

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Answer 1 · 2016-11-18T17:59:38

#x < 0#

First subtract 5 from each side of the inequality to begin to isolate and solve for #x# while keeping the inequality balanced:

#5 + 3x - 5 < 5 - 5#

#3x + 0 < =#

#3x < 0#

Next divide each side of the inequality by #3# to solve for #x# while keeping the inequality balanced:

#(3x)/3 < 0/3#

#1x < 0#

#x < 0#