Question

How do you solve `log_10(x^2+1)=1`?

Answer 1

`x=+-3`

Explanation:

`log_ab=c=>a^c=b`

`log_10(x^2+1)=1=>10^1=x^2+1`

`x^2+1=10`

`x^2=9`
`x=sqrt9=+-3`