How do you solve #|x - 3| + 1= 3#?

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Answer 1 · 2016-11-20T14:35:20

#x = 5# and #x = 1#

First, isolate the absolute value term on the left side of the equation:

#abs(x - 3) + 1 - 1 = 3 - 1#

#abs(x-3) = 2#

Next solve the term within the absolute value for both 2 and -2#

#x - 3 = 2#

#x - 3 + 3 = 2 + 3#

#x = 5#

and

#x - 3 = -2#

#x -3 + 3 = -2 + 3#

#x = 1#