How do you solve #x+ 7- \frac { 8x } { 3} = \frac { 18} { 6} - \frac { 5x } { 2}#?

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Answer 1 · 2016-11-20T17:12:40

#x=-4 4/5#

#x+7-(8x)/3=18/6-(5x)/2#

Multiply all terms by #6#.

#6x+42-(6xx(8x)/3)=(6xx18/6)-(6xx(5x)/2)#

Simplify.

#6x+42-(2xx8x)=(18)-(3xx5x)#

#6x+42-16x=18-15x#

#42-10x=18-15x#

Add #15x# to each side.

#42+5x=18#

Subtract #42# from both sides.

#5x=-24#

Divide both sides by #5#.

#x=-24/5#

#x=-4 4/5#