How do you multiply #\frac { 9( r + 4) } { r + 4} \cdot \frac { 9r } { 9( r - 5) }#?

1 Answer
Nov 20, 2016

#-1/5#

Explanation:

At first glance, there are a lot of things going on here. A second glance reveals that the you can eliminate a lot of it by reducing and/or cross multiplication/division. Check this out:

#(9(r + 4))/(r + 4) * (9r)/(9(r - 5))#

See those #(r + 4)#'s on the left? Scrap 'em.

#9/1 * (9r)/(9(r - 5))#

Expand the denominator on the right. That'll give you something else to eliminate (the #9r#'s).

#9/1 * (9r)/(9r - 45)#

#9/1 * 1/-45#

We can now reduce the numerator #9# and the denominator #-45# as they have a GCF of 9.

#1/1 * 1/-5#

Since #1/1# is #1#, we can ignore that and we are left with #-1/5#.