Question

How do you find the critical points for `g(x)=2x^3-3x^2-12x+5`?

Answer 1

Find the first derivative and set the equation to equal zero.

Explanation:

`g'(x) = 6x^2-6x-12`
`=6(x^2-x-2)=6(x-2)(x+1)`

`6(x-2)(x+1)=0`

Critical Values:
`x=2, x=-1`