Question

Is `f(x)=(x^3-3x^2-5x+2)/(x+1)` increasing or decreasing at `x=0`?

Answer 1

Decreasing.

Explanation:

`f'(x)=[(3x^2-6x-5)(x+1)-(x^3-3x^2-5x+2)]/(x+1)`

`=(2x^3-x-7)/(x+1)`

`f'(0) = -7 =>` Decreasing at `x=0`