How do you find the derivative of $3^x$ ?

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Answer 1 · 2016-11-23T15:39:08

$(dy)/(dx)=3^xln3$

using logarithmic differentiation

$y=3^x$

take natural logs to both sides

$lny=ln3^x=xln3$

differentiate $wrt" " x$

$1/y(dy)/(dx)=ln3$

$(dy)/(dx)=yln3$

substitute back

$(dy)/(dx)=3^xln3$

How do you find the derivative of 3^x3^x?