Question

How do you solve `x/6+3/2=(2x)/3-1` and check for extraneous solutions?

Answer 1

`x=5`

Explanation:

`x/6+3/2=(2x)/3-1`

One way to do it is to write everything with the same denominator:
`x/6+9/6=(4x)/6-6/6`
x+9=4x-6##

Subtract 4x +9 from each side:
`-3x=-15`

Divide each side by -3:
`x=5`