How do you solve the quadratic $4 x^{2} + 4 = - 29$ $4x^2+4=-29$ using any method?

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Answer 1 · 2016-11-23T21:12:50

$4 x^{2} + 4 = - 29$ $4x^2+4=-29$
$4 x^{2} = - 33$ $4x^2=-33$

$x^{2} = \frac{- 33}{4}$ $x^2=(-33)/(4)$
$x^{2} = - 8.25$ $x^2=-8.25$

$x = \pm i \sqrt{8.25}$ $x=+-isqrt(8.25)$

How do you solve the quadratic 4x2+4=−294x^2+4=-29 using any method?