How do you simplify $(x - 2 + 3 i) (x - 2 - 3 i)$ $(x-2+3i)(x-2-3i)$ ?

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How do you simplify $(x - 2 + 3 i) (x - 2 - 3 i)$ $(x-2+3i)(x-2-3i)$ ?

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Answer 1 · 2016-11-24T00:18:01

$x^{2} - 4 x - 9^{2}$ $x^2-4x-9^2$

Explanation:

$x \cdot x = x^{2}$ $x*x=x^2$
$x \cdot - 2 = - 2 x$ $x*-2=-2x$
$x \cdot - 3 i = - 3 i x$ $x*-3i=-3ix$
$- 2 \cdot x = - 2 x$ $-2*x=-2x$
$- 2 \cdot - 2 = 4$ $-2*-2=4$
$- 2 \cdot - 3 i = 6 i$ $-2*-3i=6i$
$3 i \cdot x = 3 i x$ $3i*x=3ix$
$3 i \cdot - 2 = - 6 i$ $3i*-2=-6i$
$3 i \cdot - 3 i = - 9 i^{2}$ $3i*-3i=-9i^2$
$x^{2} - 2 x - 3 i x - 2 x + 4 + 6 i + 3 i x - 6 i - 9 i^{2}$ $x^2-2x-3ix-2x+4+6i+3ix-6i-9i^2$
$x^{2} - 4 x + 9$ $x^2-4x+9$

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How do you simplify $(x - 2 + 3 i) (x - 2 - 3 i)$ $(x-2+3i)(x-2-3i)$ ?

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How do you simplify (x−2+3i)(x−2−3i)(x-2+3i)(x-2-3i)?

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How do you simplify $(x - 2 + 3 i) (x - 2 - 3 i)$ $(x-2+3i)(x-2-3i)$ ?